(2x+3)^2/3+(2x+3)^1/3-6=0

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Solution for (2x+3)^2/3+(2x+3)^1/3-6=0 equation: 


x in (-oo:+oo)

((2*x+3)^2)/3+((2*x+3)^1)/3-6 = 0

((2*x+3)^2)/3+(2*x+3)/3-6 = 0

((2*x+3)^2)/3+(2*x+3)/3+(-6*3)/3 = 0

(2*x+3)^2+2*x-6*3+3 = 0

4*x^2+14*x-18+12 = 0

4*x^2+14*x-6 = 0

4*x^2+14*x-6 = 0

2*(2*x^2+7*x-3) = 0

2*x^2+7*x-3 = 0

DELTA = 7^2-(-3*2*4)

DELTA = 73

DELTA > 0

x = (73^(1/2)-7)/(2*2) or x = (-73^(1/2)-7)/(2*2)

x = (73^(1/2)-7)/4 or x = (-(73^(1/2)+7))/4

2*(x+(73^(1/2)+7)/4)*(x-((73^(1/2)-7)/4)) = 0

(2*(x+(73^(1/2)+7)/4)*(x-((73^(1/2)-7)/4)))/3 = 0

(2*(x+(73^(1/2)+7)/4)*(x-((73^(1/2)-7)/4)))/3 = 0 // * 3

2*(x+(73^(1/2)+7)/4)*(x-((73^(1/2)-7)/4)) = 0

( x+(73^(1/2)+7)/4 )

x+(73^(1/2)+7)/4 = 0 // - (73^(1/2)+7)/4

x = -((73^(1/2)+7)/4)

( x-((73^(1/2)-7)/4) )

x-((73^(1/2)-7)/4) = 0 // + (73^(1/2)-7)/4

x = (73^(1/2)-7)/4

x in { -((73^(1/2)+7)/4), (73^(1/2)-7)/4 }

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